Question on: JAMB Mathematics - 2022
If A = \(\begin{pmatrix} 2 & 1 \ 2 & 3 \ 1 & 2 \end{pmatrix}\) and B = \(\begin{pmatrix} 3 & 2 \ 4 & 2 \end{pmatrix}\). Find AB
A
\(\begin{pmatrix} 18Â & 6Â \ 12Â & 10 \ 10 & 6Â \end{pmatrix}\)
B
\(\begin{pmatrix} 10Â & 6Â \ 13Â & 10 \ 12 & 6Â \end{pmatrix}\)
C
\(\begin{pmatrix} 10Â & 6Â \ 12Â & 10 \ 11 & 6Â \end{pmatrix}\)
D
\(\begin{pmatrix} 10Â & 6Â \ 18Â & 10 \ 11 & 6Â \end{pmatrix}\)
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Correct Option: D
To find the product AB, we need to perform matrix multiplication. Matrix A is a 3x2 matrix, and Matrix B is a 2x2 matrix. The resulting matrix will therefore be a 3x2 matrix.
Here's how to calculate the elements of the resulting matrix:
1. **Element (1,1):** (2 \* 3) + (1 \* 4) = 6 + 4 = 10
2. **Element (1,2):** (2 \* 2) + (1 \* 2) = 4 + 2 = 6
3. **Element (2,1):** (2 \* 3) + (3 \* 4) = 6 + 12 = 18
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