If a resistance is halved in value and the pote... - JAMB Physics 1995 Question
If a resistance is halved in value and the potential difference across it is tripled, then the ratio of the new current to the old one is
A
1 : 6
B
1 : 3
C
2 : 1
D
6 : 1
correct option: d
(\frac{V_1}{V_2}) = (\frac{I_1R_1}{I_2R_2})
(\frac{I_1}{I_2})V2 = 3V1 and R1 = 2R2
(\frac{V_1}{3V_1}) = (\frac{I_1 \times\ 2R_2}{I_2\times R_2})
(\frac{I_1}{I_2}) = (\frac{6}{1})
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