If cos theta x and sin 60o x 0 5 0o lt theta lt... - WAEC Mathematics 2016 Question
If cos (\theta) = x and sin 60o = x + 0.5 0o < (\theta) < 90o, find, correct to the nearest degree, the value of (\theta)
A
32o
B
40o
C
60o
D
69o
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Correct Option: D
sin 60o = x + 0.5 0o(given)
0.8660 = x + 0.5
0.8660 - 0.5 = x
x = 0.3660
cos(\theta) = x(given)
cos(\theta) = 0.3660
Hence, (\theta) = cos-1(0.3660)
= 68.53o
= 69o (nearest degree)
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