If dy dx 2x - 3 and y 3 when x 0 find y in term... - JAMB Mathematics 2002 Question
If dy/dx = 2x - 3 and y = 3 when x = 0, find y in terms of x.
A
2x2 - 3x
B
x2 - 3x
C
x2 - 3x - 3
D
x2 - 3x + 3
correct option: d
dy/dx = 2x - 3
y = ∫2x - 3 dx => y = x2 - 3x + c
3 = (0)2 - 3(0) + c
=> c = 3
Thus y = x2 - 3x + 3
y = ∫2x - 3 dx => y = x2 - 3x + c
3 = (0)2 - 3(0) + c
=> c = 3
Thus y = x2 - 3x + 3
Please share this, thanks:
Add your answer
No responses