Question on: WAEC Mathematics - 2003
If \(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\) find n
A
\(-\frac{3}{2}\)
B
\(\frac{1}{3}\)
C
-1
D
-3
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Correct Option: C
\(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\
3^{1-n}\times 3^{-2(-2n)} = 3^{-2}\
1-n-2(-2n)= -2\
1-n+4n=-2\
n=-1\)
3^{1-n}\times 3^{-2(-2n)} = 3^{-2}\
1-n-2(-2n)= -2\
1-n+4n=-2\
n=-1\)
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