Question on: WAEC Mathematics - 2003
If (\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}) find n
A
\(-\frac{3}{2}\)
B
\(\frac{1}{3}\)
C
-1
D
-3
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Correct Option: C
(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}<br /> 3^{1-n}\times 3^{-2(-2n)} = 3^{-2}<br /> 1-n-2(-2n)= -2<br /> 1-n+4n=-2<br /> n=-1)
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