Question on: JAMB Mathematics - 2024
If \(\frac{x}{a + 1} + \frac{y}{b} = 1\), make y the subject of the relation.
A
\(\frac{b(a + 1 - x)}{a + 1}\)
B
\(\frac{a + 1}{b(a - x + 1)}\)
C
\(\frac{a(b - x + 1)}{b + 1}\)
D
\(\frac{b}{a(b - x + 1)}\)
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Correct Option: A
We are given the equation:
\[ \frac{x}{a + 1} + \frac{y}{b} = 1 \]
Subtract \(\frac{x}{a + 1}\) from both sides:
\[ \frac{y}{b} = 1 - \frac{x}{a + 1} \]
Multiply both sides by b:
\[ y = b \left(1 - \frac{x}{a + 1}\right) \]
Simplify:
\[ y = \frac{b(a + 1 - x)}{a + 1} \]
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