Question on: JAMB Mathematics - 1999
If log 10 to base 8 = X, evaluate log 5 to base 8 in terms of X.
A
\(\frac{1}{2}\)X
B
X-\(\frac{1}{4}\)
C
X-\(\frac{1}{3}\)
D
X-\(\frac{1}{2}\)
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Correct Option: C
\(log_810\) = X = \(log_8{2 x 5}\)
\(log_82\) + \(log_85\) = X
Base 8 can be written as \(2^3\)
\(log_82 = y\)
therefore \(2 = 8^y\)
\(y = \frac{1}{3}\)
\(\frac{1}{3} = log_82\)
taking \(\frac{1}{3}\) to the other side of the original equation
\(log_85 = X-\frac{1}{3}\)
explanation courtesy of Oluteyu and Ifechuks
\(log_82\) + \(log_85\) = X
Base 8 can be written as \(2^3\)
\(log_82 = y\)
therefore \(2 = 8^y\)
\(y = \frac{1}{3}\)
\(\frac{1}{3} = log_82\)
taking \(\frac{1}{3}\) to the other side of the original equation
\(log_85 = X-\frac{1}{3}\)
explanation courtesy of Oluteyu and Ifechuks
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