Question on: WAEC Mathematics - 2006
If loga270 - loga10 + loga (\frac{1}{3}) = 2, what is the value of a?
A
3
B
4
C
5
D
6
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Correct Option: A
loga270 - loga10 + loga(\frac{1}{3}) = 2
loga270 + loga(\frac{1}{3}) - loga10 = 2
loga(270(\frac{\frac{1}{3}}{10})) = 2
loga9 = 2
aa = 9
a = (\sqrt{9}) = 3
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