Question on: WAEC Mathematics - 2006
If loga270 - loga10 + loga \(\frac{1}{3}\) = 2, what is the value of a?
A
3
B
4
C
5
D
6
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Correct Option: A
loga270 - loga10 + loga\(\frac{1}{3}\) = 2
loga270 + loga\(\frac{1}{3}\) - loga10 = 2
loga(270\(\frac{\frac{1}{3}}{10}\)) = 2
loga9 = 2
aa = 9
a = \(\sqrt{9}\) = 3
loga270 + loga\(\frac{1}{3}\) - loga10 = 2
loga(270\(\frac{\frac{1}{3}}{10}\)) = 2
loga9 = 2
aa = 9
a = \(\sqrt{9}\) = 3
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