Question on: JAMB Mathematics - 2010
If P = (\begin{pmatrix} 2 & -3 \ 1 & 1 \end{pmatrix})
A
\(\begin{pmatrix} -{\frac{1}{5}} & -{\frac{3}{5}} \ -{\frac{1}{5}} & -{\frac{2}{5}} \end{pmatrix}\)
B
\(\begin{pmatrix} {\frac{1}{5}} & {\frac{3}{5}} \ {\frac{1}{5}} & {\frac{2}{5}} \end{pmatrix}\)
C
\(\begin{pmatrix} -{\frac{1}{5}} & {\frac{3}{5}} \ -{\frac{1}{5}} & {\frac{2}{5}} \end{pmatrix}\)
D
\(\begin{pmatrix} {\frac{1}{5}} & {\frac{3}{5}} \ -{\frac{1}{5}} & {\frac{2}{5}} \end{pmatrix}\)
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Correct Option: D
P = (\begin{pmatrix} 2 & -3 \ 1 & 1 \end{pmatrix})
|P| = 2 - 1 x -3 = 5
P-1 = (\frac{1}{5})(\begin{pmatrix} 1 & 3 \ -1 & 2 \end{pmatrix})
= (\begin{pmatrix} {\frac{1}{5}} & {\frac{3}{5}} \ -{\frac{1}{5}} & {\frac{2}{5}} \end{pmatrix})
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