Question on: JAMB Mathematics - 2008
If p varies inverse as the square of q and p = 8 when q =4, find q when p = 32
A
\(\pm\)16
B
\(\pm\)8
C
\(\pm\)4
D
\(\pm\)2
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Correct Option: D
P (\alpha) (\frac{1}{q^2})
p = (\frac{k}{q^2})
k = pq2
k = 8 x 42
k = 8 x 16 = 128
find k = pq2
q2 = (\frac{k}{p})
q = (\frac{k}{p})
q = (\frac{128}{32})
q = √4
q = (\pm)2
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