If sin -1 2 for 0 lt lt 360o the value of is - JAMB Mathematics 2005 Question
If sin θ = -1/2 for 0 < θ < 360o, the value of θ is
A
30o and 150o
B
150o and 210o
C
210o and 330o
D
150o and 330o
correct option: c
sin θ = -1/2
= -0.5
θ = sin-1 (0.5)
θ = 30o
Since θ is negative
θ = 180 + 30 = 210o
θ = 360 - 30 = 330o
∴θ = 210o and 330o
= -0.5
θ = sin-1 (0.5)
θ = 30o
Since θ is negative
θ = 180 + 30 = 210o
θ = 360 - 30 = 330o
∴θ = 210o and 330o
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