If sin theta cos theta find theta between 0o an... - JAMB Mathematics 1993 Question
If sin \(\theta\) = cos \(\theta\), find \(\theta\) between 0o and 360o
A
45o, 225o
B
135o, 315o
C
45o, 315o
D
135o, 225o
correct option: c
sin \(\theta\) = cos \(\theta\) 0 \(\leq\) \(\theta\) \(\leq\) 360o
The acute angle where sin \(\theta\) = cos \(\theta\) = 45o
But at the fourth Quadrant Cos \(\theta\) = +ve
at the 4th quadrant, value with respect to Q is
(360 - Q) where Q = acute angle
(360 - 45) = 315o
The two solution are 45o, 315o
The acute angle where sin \(\theta\) = cos \(\theta\) = 45o
But at the fourth Quadrant Cos \(\theta\) = +ve
at the 4th quadrant, value with respect to Q is
(360 - Q) where Q = acute angle
(360 - 45) = 315o
The two solution are 45o, 315o
Please share this, thanks:
Add your answer
No responses