Question on: JAMB Mathematics - 1993
If sin \(\theta\) = cos \(\theta\), find \(\theta\) between 0o and 360o
A
45o, 225o
B
135o, 315o
C
45o, 315o
D
135o, 225o
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Correct Option: C
sin \(\theta\) = cos \(\theta\) 0 \(\leq\) \(\theta\) \(\leq\) 360o
The acute angle where sin \(\theta\) = cos \(\theta\) = 45o
But at the fourth Quadrant Cos \(\theta\) = +ve
at the 4th quadrant, value with respect to Q is
(360 - Q) where Q = acute angle
(360 - 45) = 315o
The two solution are 45o, 315o
The acute angle where sin \(\theta\) = cos \(\theta\) = 45o
But at the fourth Quadrant Cos \(\theta\) = +ve
at the 4th quadrant, value with respect to Q is
(360 - Q) where Q = acute angle
(360 - 45) = 315o
The two solution are 45o, 315o
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