If sin x frac 5 13 and 0o leq x leq 90o find th... - WAEC Mathematics 2013 Question

Sin x = (\frac{5}{13})

0^o (\leq) x (\leq) 90^o, (cos x - tan x)

AC² = AB² + BC²

13² = 5² + BC²

169 - 25 + BC²

169 - 25 = BC²

144 = BC²

Cos x = (\frac{Adj}{Hyp}) = (\frac{12}{13})

BC = (\sqrt{144})

BC = 12

tan x = (\frac{opp}{adj} = \frac{5}{12})

BC = 12

cos x - tan x = (\frac{12}{13} - \frac{5}{12})

(\frac{144 - 65}{156} = \frac{79}{156})