Question on: WAEC Mathematics - 2013
If (\sqrt{50} - K\sqrt{8} = \frac{2}{\sqrt{2}}), find K
A
-2
B
-1
C
1
D
2
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Correct Option: D
(\sqrt{50} - K\sqrt{8} = \frac{2}{\sqrt{2}})
(\sqrt{50} - \frac{2}{\sqrt{2}}) = K(\sqrt{8})
= (\sqrt{2} \times 25 - \frac{2}{\sqrt{2}})
= K (\sqrt{4 \times 2})
(\frac{5\sqrt{2}}{1} - \frac{2}{\sqrt{2}}) = 2K(\sqrt{2})
(\frac{5\sqrt{4} - 2}{\sqrt{2}} = 2K\sqrt{2})
(\frac{10 - 2}{\sqrt{2}} = 2K \sqrt{2})
(\frac{8}{\sqrt{2}} = \frac{2K\sqrt{2}}{1})
= 2k(\sqrt{2} \times \sqrt{2}) = 8
2k (\sqrt{4}) = 8
2k x 2 = 8
4k = 8
k = (\frac{8}{4})
k = 2
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