If sqrt 50 - K sqrt 8 frac 2 sqrt 2 find K - WAEC Mathematics 2013 Question

(\sqrt{50} - K\sqrt{8} = \frac{2}{\sqrt{2}})

(\sqrt{50} - \frac{2}{\sqrt{2}}) = K(\sqrt{8})

= (\sqrt{2} \times 25 - \frac{2}{\sqrt{2}})

= K (\sqrt{4 \times 2})

(\frac{5\sqrt{2}}{1} - \frac{2}{\sqrt{2}}) = 2K(\sqrt{2})

(\frac{5\sqrt{4} - 2}{\sqrt{2}} = 2K\sqrt{2})

(\frac{10 - 2}{\sqrt{2}} = 2K \sqrt{2})

(\frac{8}{\sqrt{2}} = \frac{2K\sqrt{2}}{1})

= 2k(\sqrt{2} \times \sqrt{2}) = 8

2k (\sqrt{4}) = 8

2k x 2 = 8

4k = 8

k = (\frac{8}{4})

k = 2