If sqrt 72 sqrt 32 - 3 sqrt 18 x sqrt 8 Find th... - WAEC Mathematics 2011 Question

(\sqrt{2} + \sqrt{32} - 3\sqrt{18} = x\sqrt{8})

= (\sqrt{36 \times 2} + \sqrt{16 \times 2} - 3\sqrt{2 \times 9})

= x(\sqrt{2 \times 4})

= 6(\sqrt{2} + 4\sqrt{2} - 9\sqrt{2} = 2 \times \sqrt{2})

(\sqrt{2} (6 + 4 - 9) = 2x\sqrt{2})

(\sqrt{2} = 2x \sqrt{2}) divide both sides by (\sqrt{2})

(\frac{\sqrt{2}}{\sqrt{2}} = \frac{2 \times \sqrt{2}}{\sqrt{2}})

1 = 2x

2x = 1

x = (\frac{1}{2})