Question on: JAMB Physics - 1995
If the maximum voltage across a 100ohms resistor is 20V, then the maximum power it can dissipate is
A
5.00W
B
4.00W
C
2.00W
D
25W
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Correct Option: B
P = \(\frac{V^2}{R}\)
= \(\frac{20 \times 20}{100}\)
= 4W
= \(\frac{20 \times 20}{100}\)
= 4W
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