Question on: JAMB Mathematics - 2006
If the mean of five consecutive integers is 30, find the largest of the numbers
A
28
B
30
C
32
D
34
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Correct Option: C
Let the consecutive numbers be a, a+1, a+2, a+3, a+4
Mean = \(\frac{(a+a+1+a+2+a+3+a+4)}{5}\\ 30 = \frac{5a+10}{5}\\ 30 \times 5 = 5a + 10\\ 5a = 150 - 10\\ 5a = 140\\ a = 28 \\ ∴ a + 4 = 28 + 4\\ = 32\)
Mean = \(\frac{(a+a+1+a+2+a+3+a+4)}{5}\\ 30 = \frac{5a+10}{5}\\ 30 \times 5 = 5a + 10\\ 5a = 150 - 10\\ 5a = 140\\ a = 28 \\ ∴ a + 4 = 28 + 4\\ = 32\)
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