Question on: JAMB Chemistry - 2020

If the quantity of oxygen occupying 2.76L container at a pressure of 0.825 atm and 300k is reduced by one-half, what is the pressure exerted by the remaining gas?

A

1.650atm

B

0.825atm

C

0.413atm

D

0.275atm

Ask EduPadi AI for a detailed answer
Correct Option: A

By applying the combined gas law formula,

Given:

P\(_1\) = 0.825,   V\(_1\) = 2.76 L, V\(_2\) = 1.38 L, P\(_2\) = ?

T1 = T2; we would have P\(_2\) = [ P\(_1\) X V\(_1\) ] ÷ V\(_2\)

[0.825 X 2.76]  ÷ 1.38

= 1.650atm

Add your answer

Notice: Please post responsibly.

Please share this, thanks!

No responses