Question on: JAMB Mathematics - 2010
If three unbiased coins are tossed, find the probability that they are all heads
A
\(\frac{1}{2}\)
B
\(\frac{1}{3}\)
C
\(\frac{1}{9}\)
D
\(\frac{1}{8}\)
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Correct Option: D
P(H) = (\frac{1}{2}) and P(T) = (\frac{1}{2})
Using the binomial prob. distribution,
(H + T)3 = H3 + 3H2T1 + 3HT2 + T3
Hence the probability that three heads show in a toss of the three coins is H3
= ((\frac{1}{2}))3
= (\frac{1}{8})
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