Question on: JAMB Mathematics - 1993
If two angles of a triangle are 30o each and the longest side is 10cm. Calculate the length of each of the other sides
A
5cm
B
4cm
C
3√3 cm
D
10\(\frac{3}{3}\)cm
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Correct Option: D
102 = 2x2 - 2x2 cos 120o (Cosine rule)
100 = 242 - 2x2 - 2x2 x -(\frac{1}{2})
100 = 3x2 + x2
= 3x2
x = (\sqrt{\frac{100}{3}})
= (\frac{10}{\sqrt{3}}) x (\frac{3}{\sqrt{3}})
x = 10(\frac{3}{3})cm
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