If two graphs y = px2 + q and y = 2x2 -1 intersect at x = 2, find the value of p in terms q.
Correct Option:
B
\(y = px^{2}+q\y = 2x^{2}-1\\Rightarrow px^{2}+q=2x^{2}-1\px^{2}=2x^{2}-1-q\p=\frac{(2x^{2}-q-1)}{x^{2}}\At\hspace{1mm}x=2\p=\frac{2(2^{2})-1-q)}{2^{2}}\p=\frac{(8-1-q)}{4}\=\frac{7-q}{4}\)