Question on: WAEC Mathematics - 2002
If (x + 3) varies directly as y and x = 3 when y = 12, what is the value of x when y = 8?
A
1
B
\(\frac{1}{2}\)
C
\(-\frac{}{}\)
D
-1
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Correct Option: A
\((x+3) \propto y\
∴x + 3 = ky\hspace{1mm}when\hspace{1mm}x = 3, y = 12\
3+3 = 12k\
∴ k = \frac{1}{2}\
\Longrightarrow x + 3 = \frac{1}{2}y\) to find x when y = 8
\(x + 3 = \frac{1}{2}\times 8\
x=4-3\
x = 1\)
∴x + 3 = ky\hspace{1mm}when\hspace{1mm}x = 3, y = 12\
3+3 = 12k\
∴ k = \frac{1}{2}\
\Longrightarrow x + 3 = \frac{1}{2}y\) to find x when y = 8
\(x + 3 = \frac{1}{2}\times 8\
x=4-3\
x = 1\)
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