Question on: JAMB Mathematics - 1990
If x + \(\frac{1}{x}\) = 4, find x2 + \(\frac{1}{x^2}\)
A
16
B
14
C
12
D
9
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Correct Option: B
x + \(\frac{1}{x}\) = 4, find x2 + \(\frac{1}{x^2}\)
= (x + \(\frac{1}{x}\))2 = x2 + \(\frac{1}{x^2}\) + 2
x2 + \(\frac{1}{x^2}\) = ( x + \(\frac{1}{x^2}\))2 - 2
= (4)2 - 2
= 16 - 2
= 14
= (x + \(\frac{1}{x}\))2 = x2 + \(\frac{1}{x^2}\) + 2
x2 + \(\frac{1}{x^2}\) = ( x + \(\frac{1}{x^2}\))2 - 2
= (4)2 - 2
= 16 - 2
= 14
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