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If y frac y 2 sqrt x 2 m 3N make x the subject ... - WAEC Mathematics 2010 Question

If y = \(\frac{y(2\sqrt{x^2 + m})}{3N}\), make x the subject of the formular
A
\(\frac{\sqrt{9y^2 N^2 - 2m}}{3}\)
B
\(\frac{\sqrt{9y^2 N^2 - 4m}}{2}\)
C
\(\frac{\sqrt{9y^2 N^2 - 3m}}{2}\)
D
\(\frac{\sqrt{9y^2 N - 3m}}{2}\)
correct option: b

y = (\frac{y(2\sqrt{x^2 + m})}{3N})

3yN = 2((\sqrt{x^2 + m}))

(\frac{3yN}{2} = \sqrt{x^2 + m})

((\frac{3yN}{2})^2 = ( \sqrt{x^2 + m}))

(\sqrt{\frac{9y^2N^2}{4} - \frac{m}{1}})

x = (\frac{\sqrt{9Y^2N^2 - 4m}}{4})

x = (\frac{\sqrt{9y^2N^2 - 4m}}{2})

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