If y x sinx find dy dx when x 2 - JAMB Mathematics 2001 Question
If y = x sinx, find dy/dx when x = π/2.
A
-π/2
B
-1
C
1
D
π/2
correct option: c
y = x sin x
dy/dx = 1 x sinx + x cosx
= sinx + x cosx
At x = π/2, = sin (π/2) + (π/2) cos (π/2)
= 1 + (π/2) x (0) = 1
dy/dx = 1 x sinx + x cosx
= sinx + x cosx
At x = π/2, = sin (π/2) + (π/2) cos (π/2)
= 1 + (π/2) x (0) = 1
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