If y = \((x^2 + 3x − 1) ÷ (3x + 4).\) Find dy/dx
Correct Option:
A
dy/dx \( (4x^3 + 3x^2 + 2x + 1) \)
= \( 12x^2 + 6x + 2 \)
⇒ \( 12x^2 + 6 + 2 \)
Divide both sides by 2
\( \frac{12x^2}{2} − \frac{6x}2 − \frac{2}{2} \)
= \( 6x^2 + 3x + 1 \)
dy/dx
= \( 6x^2 + 3x + 1 \)
= \( 12x^2 + 6x + 2 \)
⇒ \( 12x^2 + 6 + 2 \)
Divide both sides by 2
\( \frac{12x^2}{2} − \frac{6x}2 − \frac{2}{2} \)
= \( 6x^2 + 3x + 1 \)
dy/dx
= \( 6x^2 + 3x + 1 \)