Question on: JAMB Mathematics - 2012
If y = x2 - \(\frac{1}{x}\), find \(\frac{\delta y}{\delta x}\)
A
2x - \(\frac{1}{x^2}\)
B
2x + x2
C
2x - x2
D
2x + \(\frac{1}{x^2}\)
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Correct Option: D
y = x2 - \(\frac{1}{x}\)
y = x2 - x-1
\(\frac{\delta y}{\delta x}\) = 2x + x-2
\(\frac{\delta y}{\delta x}\) = 2x + \(\frac{1}{x^2}\)
y = x2 - x-1
\(\frac{\delta y}{\delta x}\) = 2x + x-2
\(\frac{\delta y}{\delta x}\) = 2x + \(\frac{1}{x^2}\)
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