Question on: JAMB Physics - 2003
In a fission process, the decrease in mass is 0.01%. How much energy could be obtained from the fission of 0.1g of the material
A
\( 9.0 \times 10^{9}J \)
B
\( 9.0 \times 10^{10}J \)
C
\( 6.3 \times 10^{11}J \)
D
\( 9.0 \times 10^{11}J \)
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Correct Option: A
In general, the energy released during nuclear fission is given by the Einstein's mass-energy equation, given by
\( E = \Delta MC^2 \)
Where \( \Delta m\) is the mass defect, and C is the speed of light.
Therefore
\( \Delta m = 0.01% \text{of} 1.0g = \frac{0.01}{100}
\times 1.0g \\
= 1.0 \times 10^{-4} \\ = 1.0 \times 10^{-7}kg\\
\text{Energy Released } = \Delta MC^2 \\
= 1.0 \times 10^{-7} \times (3.0 \times 10^8)^2\\ = 1.0 \times 10^{-2} \times 9.0 \times 10^{16} \\
= 9.0 \times 10^9 J \)
\( E = \Delta MC^2 \)
Where \( \Delta m\) is the mass defect, and C is the speed of light.
Therefore
\( \Delta m = 0.01% \text{of} 1.0g = \frac{0.01}{100}
\times 1.0g \\
= 1.0 \times 10^{-4} \\ = 1.0 \times 10^{-7}kg\\
\text{Energy Released } = \Delta MC^2 \\
= 1.0 \times 10^{-7} \times (3.0 \times 10^8)^2\\ = 1.0 \times 10^{-2} \times 9.0 \times 10^{16} \\
= 9.0 \times 10^9 J \)
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