Question on: WAEC Physics - 1997
In a nuclear reaction, the mass defect is 2 x \(10^{-6}\)g. Calculate the energy released given that the velocity of light is 3 x \(10^{8}ms^{-1}\)
A
9 x \(10^{7}\)J
B
1.8 x \(10^{8}\)J
C
1.8 x \(10^{9}\)J
D
9 x \(10^{-10}\)J
Ask EduPadi AI for a detailed answer
Correct Option: B
E=\(mc^2 = 2\times10^{-6} \times10^{-3}\times(3\times10^{8})^2=1.8\times10^{8}\)
Add your answer
Please share this, thanks!
No responses