In a reaction SnO 2C Sn 2CO the mass of coke co... - JAMB Chemistry 1990 Question
In a reaction: SnO + 2C → Sn + 2CO, the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is?
(Sn - 119, O - 16, C - 12).
(Sn - 119, O - 16, C - 12).
A
0.40 kg
B
0.20 kg
C
0.06 kg
D
0.04 kg
correct option: c
In the reaction: SnO2 + 2CO
From the equation above
2(12 g) carbon = 151 g SnO2
24 g carbon =151 g SnO2
= 0.302 kg SnO2 = 24/151g χ 0.0302 kg carbon = 0.048 kg carbon
Mass of coke is required not mass of carbon,so it is (0.048\(\times\)100)\(\div\)80 = 0.06
From the equation above
2(12 g) carbon = 151 g SnO2
24 g carbon =151 g SnO2
= 0.302 kg SnO2 = 24/151g χ 0.0302 kg carbon = 0.048 kg carbon
Mass of coke is required not mass of carbon,so it is (0.048\(\times\)100)\(\div\)80 = 0.06
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