In a series R-L-C circuit R 10 Omega X c 4 Omeg... - WAEC Physics 2018 Question
In a series R-L-C circuit, R = 10\(\Omega\), \(X_{c}\)= 4\(\Omega\) and \(X_{L}\) = 9\(\Omega\). The impedance of the circuit is
A
4.1\(\Omega\)
B
5.0\(\Omega\)
C
10.8\(\Omega\)
D
11.2\(\Omega\)
correct option: d
The impedance (Z) for a RLC circuit is:
\(Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}\)
= \(\sqrt{10^{2} + (9 - 4)^{2}}\)
= \(\sqrt{125}\)
= 11.18\(\Omega\) \(\approxeq\) 11.2\(\Omega\)
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