Question on: JAMB Mathematics - 1997
In a triangle XYZ, if < ZYZ is 60, XY = 3cm and YZ = 4cm, calculate the length of the sides XZ.
A
√23cm
B
√13cm
C
2√5cm
D
2√3cm
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Correct Option: B
(XZ)2 = 32 + 42 - 2 x 3 x 4 cos60o
= 25 - 24\(\frac{1}{2}\)
XZ = √13cm
= 25 - 24\(\frac{1}{2}\)
XZ = √13cm
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