In how many ways can 2 students be selected fro... - JAMB Mathematics 2021 Question
In how many ways can 2 students be selected from a group of 5 students for a debating competition?
A
20 ways
B
10 ways
C
15 ways
D
25 ways
correct option: b
\(\hspace{1mm} ^{5}C_{2}\hspace{1mm}ways\hspace{1mm}=\frac{5!}{(5-2)!2!}=\frac{5!}{3!2!}=\frac{5\times4\times3!}{3!\times2\times1}=10\hspace{1mm}ways\)
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