In how many ways can 3 seats be occupied if 5 p... - JAMB Mathematics 2013 Question
In how many ways can 3 seats be occupied if 5 people are willing to sit?
A
60
B
20
C
5
D
120
correct option: a
5 people can take 3 places in;
5P3 ways, = \(\frac{5!}{(5 - 3)!}\) = \(\frac{5!}{2!}\)
= \(\frac{5 \times 4 \times 3 \times 2!}{2!}\)
= 5 x 4 x 3
= 60 ways
5P3 ways, = \(\frac{5!}{(5 - 3)!}\) = \(\frac{5!}{2!}\)
= \(\frac{5 \times 4 \times 3 \times 2!}{2!}\)
= 5 x 4 x 3
= 60 ways
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