Question on: JAMB Mathematics - 2009
In how many ways can a delegation of 3 be chosen from 5 men and 3 women, if at least 1 man and 1 woman must be included?
A
15
B
28
C
30
D
45
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Correct Option: B
\(\frac{\begin{pmatrix} 8 \ 3 \end{pmatrix}}{\begin{pmatrix} 4 \ 1 \end{pmatrix}\begin{pmatrix} 4\ 1\end{pmatrix}}\)(Two boys and a girl) OR \(\frac{\begin{pmatrix} 8 \ 3 \end{pmatrix}}{\begin{pmatrix} 4 \ 1 \end{pmatrix}\begin{pmatrix} 4\ 1\end{pmatrix}}\)(Two girls and a boy in the committee)
\(\frac{336}{24}\) or \(\frac{336}{24}\)
14 + 14
= 28
\(\frac{336}{24}\) or \(\frac{336}{24}\)
14 + 14
= 28
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