Question on: JAMB Mathematics - 2014
In how many ways can a team of 3 girls be selected from 7 girls?
A
\(\frac{7!}{3!}\)
B
\(\frac{7!}{4!}\)
C
\(\frac{7!}{3!4!}\)
D
\(\frac{7!}{2!5!}\)
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Correct Option: C
A team of 2 girls can be selected from 7 girls in (^7C_3)
( = \frac{7!}{(7 - 3)! 3!})
( = \frac{7!}{4! 3!} ways)
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