Question on: JAMB Mathematics - 2014
In how many ways can a team of 3 girls be selected from 7 girls?
A
\(\frac{7!}{3!}\)
B
\(\frac{7!}{4!}\)
C
\(\frac{7!}{3!4!}\)
D
\(\frac{7!}{2!5!}\)
Ask EduPadi AI for a detailed answer
Correct Option: C
A team of 2 girls can be selected from 7 girls in \(^7C_3\)
\( = \frac{7!}{(7 - 3)! 3!}\)
\( = \frac{7!}{4! 3!} ways\)
\( = \frac{7!}{(7 - 3)! 3!}\)
\( = \frac{7!}{4! 3!} ways\)
Add your answer
Please share this, thanks!
No responses