In how many ways can the letters LEADER be arra... - JAMB Mathematics 2018 Question

In the given word LEADER are 1L 2E 1A 1D and 1R making total of 6! \(\frac{6}{1!2!1!1!1!}\) = \(\frac{6!}{2!}\)

  = \(\frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1}\)

  = 360