Question on: JAMB Mathematics - 2004
In how many ways can2 students be selected from a group of 5 students in a debating competition?
A
25 ways
B
10 ways
C
15 ways
D
20 ways
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Correct Option: B
\(In\hspace{1mm} ^{5}C_{2}\hspace{1mm}ways\hspace{1mm}=\frac{5!}{(5-2)!2!}\=\frac{5!}{3!2!}\=\frac{5\times4\times3!}{3!\times2\times1}\=10\hspace{1mm}ways\)
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