Question on: WAEC Mathematics - 1995

In the diagram above, AB//CD, the bisector of ∠BAC and ∠ACD meet at E. Find the value of ∠AEC

30^o

45^o

60^o

75^o

Ask EduPadi AI for a detailed answer

Correct Option: E

Ae is a bisector of BAC => EAC = 45^o
CE is the bisector of ACD => ACE = 45^o
AEC = 180^o - [EAC + ACE]
= 180^o - (45^o + 45^o) = 180^o - 90^o = 90^o

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