Question on: WAEC Mathematics - 1992
In the diagram above, O is the center of the circle PQRS and ∠QPS = 36°. Find ∠QOS
A
36o
B
72o
C
108o
D
144o
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Correct Option: B
< QOS = 2 < QPS (angle subtended at the centre)
\(\therefore\) < QOS = 2 x 36° = 72°
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