In the diagram above PQ 10 cm PS 8 cm and PSR i...

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In the diagram above, PQ = 10 cm, PS = 8 cm and ∠PSR is 60^o while ∠SRQ is a right angle. Find SR

Correct Option: A

In ΔPST; cos 60 = ^ST/₈
ST = 8cos 60
ST = 8 x ¹/₂ = 4
TR = 10 cm (opp. sides of a rectangle PQRT)
SR = ST + TR
SR = 4 + 10
SR = 14 cm