In the diagram above PQ 10 cm PS 8 cm and PSR i... - JAMB Mathematics 2006 Question
A
14 cm
B
14√3 cm
C
10 cm
D
10√3 cm
correct option: a
In ΔPST; cos 60 = ST/8
ST = 8cos 60
ST = 8 x 1/2 = 4
TR = 10 cm (opp. sides of a rectangle PQRT)
SR = ST + TR
SR = 4 + 10
SR = 14 cm
ST = 8cos 60
ST = 8 x 1/2 = 4
TR = 10 cm (opp. sides of a rectangle PQRT)
SR = ST + TR
SR = 4 + 10
SR = 14 cm
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