Question on: WAEC Mathematics - 1990
In the diagram above, PQ is a tangent at T to the circle ABT. ABC is a straight line and TC bisects ∠BTO. Find x.
A
20o
B
30o
C
35o
D
40o
Ask EduPadi AI for a detailed answer
Correct Option: E
From the figure < TAB = < BTQ = 40° (alternate segment)
\(\therefore\)< ATB = 180° - (70° + 40°) = 70° (angle on a straight line)
< BTC = \(\frac{40°}{2} = \frac{< BTQ}{2}\)
\(\therefore < BTQ = 40°\)
x° = 180° - (40° + 70° + 20°)
= 50°
Add your answer
Please share this, thanks!
No responses