Question on: JAMB Mathematics - 2003

In the diagram above, PQR is a straight line and PS is a tangent to the circle QRS with /PS/ = /SR/ and ∠SPR = 40o. Find ∠PSQ
A
40o
B
30o
C
20o
D
10o
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Correct Option: A

R = P (base ∠s of isc Δ, ps = RS)

∴R = 40o

∠PSQ = R (∠s in alternate segment)

∴∠PSQ = 40o

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