In the diagram above QR is the diameter of the ... - JAMB Mathematics 2006 Question
In the diagram above, |QR| is the diameter of the semicircle QR. Find the area of the figure to the nearest whole number. {\(\pi = \frac{22}{7}\)}
A
90cm2
B
89cm2
C
80cm2
D
70cm2
correct option: a
Area of PQRS = length x breath(7 x 10)cm2 = 70
Area of semi-circle \(\frac{1}{2} \pi r^2 = \frac{1}{2} \times \frac{22}{7} \times \frac{7}{2}\)
= 19.5cm2 = 20cm2(appr.)
Area of the figure = (70 + 20)cm2
= 90cm2
Area of semi-circle \(\frac{1}{2} \pi r^2 = \frac{1}{2} \times \frac{22}{7} \times \frac{7}{2}\)
= 19.5cm2 = 20cm2(appr.)
Area of the figure = (70 + 20)cm2
= 90cm2
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