In the diagram above QRS is a straight line QP ... - WAEC Mathematics 1993 Question
In the diagram above, QRS is a straight line, QP//RT, PRQ = 56°, ∠QPR =84° and ∠TRS = x°. Find x
A
28°
B
40°
C
44°
D
84°
correct option: b
< PQR = 180° - (84° + 56°)
= 40°
\(\therefore\) x = 40° (corresponding angles QP// RT)
Please share this, thanks:
Add your answer
No responses