In the diagram EFGH is a cyclic quadrilateral i... - JAMB Mathematics 1999 Question

A
34o
B
42o
C
52o
D
76o
correct option: c
< EFH = < EGH = 34o (angles n the same segment)
< GHF = < GEF = 42o(angles in the same segment)
< FOG = 42 + 34 = 76(exterior angle)
< FOG = < EOH = 76(vertically opposite angle)
< EDO = 90o, < DOE = (\frac{76}{2}) = 38o
< HEG = 90o - 38o = 52o
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