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In the diagram IG is parallel to JE JEF 120o an... - WAEC Mathematics 2009 Question

In the diagram, IG is parallel to JE, JEF = 120^o and FHG = 130^o, fins the angle marked t

A

40^o

B

70^o

C

80^o

D

100^o

correct option: b

Now, t + 60^o + 50^o = 180^o

t = 180^o - 110^o

t = 70^o

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