IN the diagram LN 4cm LNM 90o and tan y 2 3 Wha... - WAEC Mathematics 2007 Question
IN the diagram, |LN| = 4cm, LNM = 90o and tan y = 2/3. What is the area of the ∆LMN?
A
24cm2
B
12cm2
C
10cm2
D
6cm2
correct option: b
\(tan \hspace{1mm}y = \frac{opp}{adj}=\frac{2}{3}\Rightarrow \frac{2}{3}=\frac{
LN}{MN}=\frac{4}{MN}\
∴ MN = \frac{12}{2}=6\
Area \hspace{1mm}of \hspace{1mm}\Delta LMN = \frac{1}{2}\times MN\times LN=\frac{1}{2}\times 6\times 4=12cm\)
LN}{MN}=\frac{4}{MN}\
∴ MN = \frac{12}{2}=6\
Area \hspace{1mm}of \hspace{1mm}\Delta LMN = \frac{1}{2}\times MN\times LN=\frac{1}{2}\times 6\times 4=12cm\)
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