In the diagram lt QPR 60o lt PQR 50o lt QRS 2xo... - WAEC Mathematics 2008 Question

< RQT = < QRS = 2x (Alternate angles). But in (\bigtriangleup) PRQ

50 + 60 + (2x + 3x) = 180^o(Angles in a triangle)

110 + 5x = 180^o

5x = 180^o - 110 = 70^o

x = (\frac{70}{5}) = 14^o

Also y + 50 + 2(14) = 180^o

y + 50 + 28 = 180^o

y = 180 - 78

y = 102^o