Question on: WAEC Mathematics - 2010
In the diagram, < ROS = 66o and < POQ = 3x. some construction lines are shown. Calculate the value of x.
A
10o
B
11o
C
22o
D
35o
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Correct Option: B
From the diagram, OP bisects < ROS
< POS = \(\frac{1}{2}\) < ROS = \(\frac{1}{2}\) x 66o
3x = 33o
x = \(\frac{33^o}{3}\)
= 11o
< POS = \(\frac{1}{2}\) < ROS = \(\frac{1}{2}\) x 66o
3x = 33o
x = \(\frac{33^o}{3}\)
= 11o
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